P=AF
Problem 1: The High Heels vs. Flat Shoes
A girl weighs 500 N.
- Case A: She wears flat shoes with a total sole area of 0.05 m2.
- Case B: She wears high heels where the weight is concentrated on a heel area of just 0.001 m2 (assume she stands on one heel for a moment).
Calculate the pressure in both cases.
Click to Reveal Solution
Case A (Flats):
P=0.05500=5/100500=500×20=10,000 Pa
Case B (Heels):
P=0.001500=1/1000500=500×1000=500,000 Pa
Observation: The heels exert 50 times more pressure! This is why heels sink into grass.
Problem 2: The Brick
A brick has dimensions 20 cm×10 cm×5 cm and weighs 20 N.
Calculate the maximum and minimum pressure it can exert on the ground.
Hint: Max pressure occurs on the smallest area. Min pressure occurs on the largest area.
Click to Reveal Solution
Step 1: Calculate Areas (convert to meters!)
- Face 1 (20×10): 0.2×0.1=0.02 m2
- Face 2 (20×5): 0.2×0.05=0.01 m2 (Smallest Area)
- Face 3 (10×5): 0.1×0.05=0.005 m2 … Wait.
- 20×10=200 cm2
- 20×5=100 cm2
- 10×5=50 cm2 (Smallest Area is actually this one).
Correction:
- Largest Area (20×10): 0.02 m2.
- Smallest Area (10×5): 0.005 m2.
Step 2: Calculate Pressure
- Minimum Pressure (Largest Area):
P=0.0220=1000 Pa
- Maximum Pressure (Smallest Area):
P=0.00520=4000 Pa