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Overview

Page 146-147: House Plans

April 10, 2024
1 min read

Charan’s House (Page 146)

Total Plot: Length = 35 ft, Width = 30 ft. Total Area: 35×30=1050 sq ft35 \times 30 = 1050\text{ sq ft}.

Room Dimensions:

  1. Small Bedroom:
    • Given Area = 180 sq ft. Length = 15 ft.
    • Width = 180/15=12 ft180 / 15 = 12\text{ ft}.
  2. Utility:
    • Dimensions derived from remaining space.
    • Width = Total Width (30) - Kitchen (12) - Toilet (5)? No, looking at layout:
    • Top row: Master Bed (15) + Toilet (5) + Utility (?). Total = 35? No, Master bed is square 15×1515 \times 15.
    • Let’s check alignment.
    • Solution: Utility is 15 ft×3 ft15\text{ ft} \times 3\text{ ft}. Area = 45 sq ft.
  3. Hall:
    • Dimensions: 20 ft×12 ft20\text{ ft} \times 12\text{ ft}.
    • Area: 240 sq ft240\text{ sq ft}.
  4. Parking:
    • 15 ft×3 ft15\text{ ft} \times 3\text{ ft}. Area = 45 sq ft.
  5. Garden:
    • 20 ft×3 ft20\text{ ft} \times 3\text{ ft}. Area = 60 sq ft.

Sharan’s House (Page 147)

Total Plot: 42 ft (Width) ×\times 25 ft (Height). Total Area: 42×25=1050 sq ft42 \times 25 = 1050\text{ sq ft}.

Comparison:

  • Area: Both houses have the same area (1050 sq ft1050\text{ sq ft}).
  • Perimeter:
    • Charan: 2×(35+30)=130 ft2 \times (35 + 30) = 130\text{ ft}.
    • Sharan: 2×(42+25)=134 ft2 \times (42 + 25) = 134\text{ ft}.
    • Conclusion: Sharan’s house has a greater perimeter.
Note

Key Takeaway: Two shapes can have the same area but different perimeters.