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Practice Puzzle: Summing to 1

January 15, 2025
1 min read

The Problem

It is easy to add the same fractional unit to get 1: 12+12=1\frac{1}{2} + \frac{1}{2} = 1 13+13+13=1\frac{1}{3} + \frac{1}{3} + \frac{1}{3} = 1

Challenge: Can you write 1 as the sum of three different fractional units?

The Solution

We need three unit fractions: 1a+1b+1c=1\frac{1}{a} + \frac{1}{b} + \frac{1}{c} = 1

Let’s start with the biggest unit fraction: 12\frac{1}{2}. Remaining needed: 12\frac{1}{2}. Now we need two different fractions that add up to 12\frac{1}{2}. We know 14+14=12\frac{1}{4} + \frac{1}{4} = \frac{1}{2}, but they must be different.

Let’s try 13\frac{1}{3}. 12+13=36+26=56\frac{1}{2} + \frac{1}{3} = \frac{3}{6} + \frac{2}{6} = \frac{5}{6}. We are short by 16\frac{1}{6}. Wait! That’s a unit fraction!

So: 12+13+16=1\frac{1}{2} + \frac{1}{3} + \frac{1}{6} = 1

1/21/31/6

Try This: Can you find four different fractional units that add up to 1?