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Solved Examples

April 10, 2024
2 min read

Example 1: Is 324 a perfect square?

Question: Determine if 324 is a perfect square using prime factorization.

Solution:

  1. Factorize 324: 324=2×162=2×2×81=2×2×9×9=2×2×3×3×3×3324 = 2 \times 162 = 2 \times 2 \times 81 = 2 \times 2 \times 9 \times 9 = 2 \times 2 \times 3 \times 3 \times 3 \times 3
  2. Group factors: (2×2)×(3×3)×(3×3)(2 \times 2) \times (3 \times 3) \times (3 \times 3)
  3. Since all factors can be paired completely with no remainders, Yes, 324 is a perfect square.
  4. 324=2×3×3=18\sqrt{324} = 2 \times 3 \times 3 = 18.

Example 2: Is 156 a perfect square?

Question: Check 156.

Solution:

  1. Factorize 156: 156=2×78=2×2×39=2×2×3×13156 = 2 \times 78 = 2 \times 2 \times 39 = 2 \times 2 \times 3 \times 13
  2. Group factors: (2×2)×3×13(2 \times 2) \times 3 \times 13
  3. The factors 3 and 13 do not have pairs.
  4. No, 156 is not a perfect square.

Example 3: Estimating 1936\sqrt{1936}

Question: Find the square root of 1936 by estimation.

Solution:

  1. Find Range: 402=160040^2 = 1600 and 502=250050^2 = 2500. 1936 is between them.
  2. Check Unit Digit: 1936 ends in 6. The root must end in 4 or 6.
  3. Possibilities: 44 or 46.
  4. Narrow Down: 452=202545^2 = 2025.
  5. Since 1936<20251936 < 2025, the root must be less than 45.
  6. Therefore, the root is 44.

Example 4: Is 3375 a perfect cube?

Question: Check if 3375 is a perfect cube.

Solution:

  1. Factorize 3375: 3375=5×675=5×5×135=5×5×5×273375 = 5 \times 675 = 5 \times 5 \times 135 = 5 \times 5 \times 5 \times 27 3375=5×5×5×3×3×33375 = 5 \times 5 \times 5 \times 3 \times 3 \times 3
  2. Group in triplets: (5×5×5)×(3×3×3)(5 \times 5 \times 5) \times (3 \times 3 \times 3)
  3. All factors form triplets. Yes, it is a perfect cube.
  4. 33753=5×3=15\sqrt[3]{3375} = 5 \times 3 = 15.