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Solved Examples & Practice

January 20, 2025
1 min read

Topic: Calculating Least Count

Example 1: A thermometer has markings at 0C0^\circ C and 5C5^\circ C. There are 5 divisions between these two marks. What is the smallest temperature this thermometer can measure?

Solution:

  1. Difference in temperature: 50=5C5 - 0 = 5^\circ C.
  2. Number of divisions: 5.
  3. Least Count: 55=1C\frac{5}{5} = 1^\circ C. Answer: The thermometer can measure a minimum change of 1C1^\circ C.

Example 2: A thermometer has markings at 10C10^\circ C and 20C20^\circ C. There are 20 divisions between these marks. What is the reading if the liquid is at the 3rd division after 15C15^\circ C?

Solution:

  1. Calculate Least Count:
    • Difference = 2010=10C20 - 10 = 10^\circ C.
    • Divisions = 20.
    • Least Count = 1020=0.5C\frac{10}{20} = 0.5^\circ C.
  2. Read the Value:
    • Base mark = 15C15^\circ C.
    • Additional reading = 3 divisions ×\times 0.5C0.5^\circ C = 1.5C1.5^\circ C.
    • Total Temperature = 15+1.5=16.5C15 + 1.5 = 16.5^\circ C.

Topic: Temperature Scales

Example 3: The temperature of a liquid is 27C27^\circ C. What is this temperature in the Kelvin scale?

Solution: We know the formula:

T(K)=T(C)+273.15T_{(K)} = T_{(^\circ C)} + 273.15 T(K)=27+273.15T_{(K)} = 27 + 273.15 T(K)=300.15KT_{(K)} = 300.15 K
Tip

Remember: Kelvin (K) does not have a degree symbol (°).