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Solved Examples

April 10, 2024
1 min read

Example 1: The Mine Shaft

Problem: A lift in a mine moves at a speed of 5 meters per minute. It starts from 10 meters above the ground.

  1. Where will it be after 1 hour if it moves down?
  2. How long will it take to reach -350 meters?

Solution

Part 1: Position after 1 hour

  • Start Position: +10+10 m.
  • Speed: 55 m/min downwards (5-5).
  • Time: 11 hour = 6060 minutes.
  • Total Movement: 60×(5)=30060 \times (-5) = -300 m.
  • Final Position: Start+Movement=10+(300)=290\text{Start} + \text{Movement} = 10 + (-300) = -290 m.
  • Answer: 290 meters below ground.

Part 2: Time to reach -350m

  • Target: 350-350.
  • Start: +10+10.
  • Distance to travel: TargetStart=35010=360\text{Target} - \text{Start} = -350 - 10 = -360 m.
  • The lift must travel 360 meters down.
  • Speed: 5m/min.
  • Time: 360÷5=72360 \div 5 = 72 minutes.
  • Answer: 1 hour and 12 minutes.

Example 2: Magic Square

In a magic square, each row, column, and diagonal sums to the same number. Check if this is a magic square:

5-1-4
-5-27
03-3

Check Rows:

  1. 5+(1)+(4)=05 + (-1) + (-4) = 0
  2. 5+(2)+7=0-5 + (-2) + 7 = 0
  3. 0+3+(3)=00 + 3 + (-3) = 0

Check Columns:

  1. 5+(5)+0=05 + (-5) + 0 = 0
  2. 1+(2)+3=0-1 + (-2) + 3 = 0
  3. 4+7+(3)=0-4 + 7 + (-3) = 0

Check Diagonals:

  1. 5+(2)+(3)=05 + (-2) + (-3) = 0
  2. 4+(2)+0=6-4 + (-2) + 0 = -6 (Wait! This is not 0).

Conclusion: Since one diagonal sums to -6, this is NOT a magic square.